What are the solutions to the equation (z^2)/6-z/2-3=0 ?

The solutions to the equation (z^2)/6-z/2-3=0 are z=6,z=-3

Find the zeros of (z^2)/6-z/2-3=0

The zeros of (z^2)/6-z/2-3=0 are z=6,z=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{z ^{2}}{6} - \frac{z}{2} - 3 = 0

z = 6, z = - 3

Solution steps

\frac{z ^{2}}{6} - \frac{z}{2} - 3 = 0

Find Least Common Multiplier of

6, 2 : 6

Multiply by LCM=

6

\frac{z ^{2}}{6} \cdot 6 - \frac{z}{2} \cdot 6 - 3 \cdot 6 = 0 \cdot 6

Simplify

z^{2} - 3 z - 18 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 18) = 9

z_{1, 2} = \frac{- ( - 3 ) \pm 9}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- ( - 3 ) + 9}{2 \cdot 1}, z_{2} = \frac{- ( - 3 ) - 9}{2 \cdot 1}

z = \frac{- ( - 3 ) + 9}{2 \cdot 1} : 6

z = \frac{- ( - 3 ) - 9}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

z = 6, z = - 3

713

2 a \cdot a

x - 5 < 5

8 (x + 3) > 12 (1 - x)

\frac{2 a ^{- 3} b ^{- 2}}{4 a ^{- 6} b ^{8}}

What are the solutions to the equation (z^2)/6-z/2-3=0 ?
The solutions to the equation (z^2)/6-z/2-3=0 are z=6,z=-3
Find the zeros of (z^2)/6-z/2-3=0
The zeros of (z^2)/6-z/2-3=0 are z=6,z=-3