What is ((x-1)(x+2))/((x-3))>= 0 ?

The solution to ((x-1)(x+2))/((x-3))>= 0 is -2 3

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((x-1)(x+2))/((x-3))>= 0

\frac{( x - 1 ) ( x + 2 )}{( x - 3 )} \geq 0

- 2 \leq x \leq 1 or x > 3

Interval Notation

[- 2, 1] \cup (3, \infty)

Solution steps

\frac{( x - 1 ) ( x + 2 )}{x - 3} \geq 0

Identify the intervals

- 2 \leq x \leq 1 or x > 3

c^{3} + 8 d^{3}

- \frac{9}{4} v + \frac{4}{5} = \frac{7}{8}

- 3 x^{2} + 2 x + 1 = 0

What is ((x-1)(x+2))/((x-3))>= 0 ?
The solution to ((x-1)(x+2))/((x-3))>= 0 is -2<= x<= 1\lor x>3