What are the solutions to the equation -2p^2-5p+7=0 ?

The solutions to the equation -2p^2-5p+7=0 are p=-7/2 ,p=1

Find the zeros of -2p^2-5p+7=0

The zeros of -2p^2-5p+7=0 are p=-7/2 ,p=1

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- 2 p^{2} - 5 p + 7 = 0

p = - \frac{7}{2}, p = 1

Decimal Notation

p = - 3.5, p = 1

Solution steps

- 2 p^{2} - 5 p + 7 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 ( - 2 ) \cdot 7}{2 ( - 2 )}

(- 5)^{2} - 4 (- 2) \cdot 7 = 9

p_{1, 2} = \frac{- ( - 5 ) \pm 9}{2 ( - 2 )}

Separate the solutions

p_{1} = \frac{- ( - 5 ) + 9}{2 ( - 2 )}, p_{2} = \frac{- ( - 5 ) - 9}{2 ( - 2 )}

p = \frac{- ( - 5 ) + 9}{2 ( - 2 )} : - \frac{7}{2}

p = \frac{- ( - 5 ) - 9}{2 ( - 2 )} : 1

The solutions to the quadratic equation are:

p = - \frac{7}{2}, p = 1

4 - x < 9

lo g_{5} (5^{2})

1 + 25 a^{2} = 2

25 p^{2} - 40 p + 16 = 0

What are the solutions to the equation -2p^2-5p+7=0 ?
The solutions to the equation -2p^2-5p+7=0 are p=-7/2 ,p=1
Find the zeros of -2p^2-5p+7=0
The zeros of -2p^2-5p+7=0 are p=-7/2 ,p=1