What are the solutions to the equation 9v^2+11v+5=4v^2 ?

The solutions to the equation 9v^2+11v+5=4v^2 are v=(-11+sqrt(21))/(10),v=(-11-sqrt(21))/(10)

Find the zeros of 9v^2+11v+5=4v^2

The zeros of 9v^2+11v+5=4v^2 are v=(-11+sqrt(21))/(10),v=(-11-sqrt(21))/(10)

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9 v^{2} + 11 v + 5 = 4 v^{2}

v = \frac{- 11 + 21}{10}, v = \frac{- 11 - 21}{10}

Decimal Notation

v = - 0.64174 \dots, v = - 1.55825 \dots

Solution steps

9 v^{2} + 11 v + 5 = 4 v^{2}

Move

4 v^{2}

to the left side

5 v^{2} + 11 v + 5 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 5 \cdot 5}{2 \cdot 5}

1 1^{2} - 4 \cdot 5 \cdot 5 = 21

v_{1, 2} = \frac{- 11 \pm 21}{2 \cdot 5}

Separate the solutions

v_{1} = \frac{- 11 + 21}{2 \cdot 5}, v_{2} = \frac{- 11 - 21}{2 \cdot 5}

v = \frac{- 11 + 21}{2 \cdot 5} : \frac{- 11 + 21}{10}

v = \frac{- 11 - 21}{2 \cdot 5} : \frac{- 11 - 21}{10}

The solutions to the quadratic equation are:

v = \frac{- 11 + 21}{10}, v = \frac{- 11 - 21}{10}

\frac{2 x ^{- 5}}{3 y ^{0}}

156 - 6 b > 114

3 x^{2} - 8 x - 60 = 0

3 x - 2 x = 11

3 (2 + y) - y = 4 + 2 (y + 1)

What are the solutions to the equation 9v^2+11v+5=4v^2 ?
The solutions to the equation 9v^2+11v+5=4v^2 are v=(-11+sqrt(21))/(10),v=(-11-sqrt(21))/(10)
Find the zeros of 9v^2+11v+5=4v^2
The zeros of 9v^2+11v+5=4v^2 are v=(-11+sqrt(21))/(10),v=(-11-sqrt(21))/(10)