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What are the solutions to the equation x^2-8x-7x=4 ?
The solutions to the equation x^2-8x-7x=4 are x=(15+sqrt(241))/2 ,x=(15-sqrt(241))/2Find the zeros of x^2-8x-7x=4
The zeros of x^2-8x-7x=4 are x=(15+sqrt(241))/2 ,x=(15-sqrt(241))/2