What are the solutions to the equation t(4-0.8t)=0 ?

The solutions to the equation t(4-0.8t)=0 are t=0,t=5

Find the zeros of t(4-0.8t)=0

The zeros of t(4-0.8t)=0 are t=0,t=5

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t (4 - 0.8 t) = 0

t = 0, t = 5

Solution steps

t (4 - 0.8 t) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

t = 0 or 4 - 0.8 t = 0

Solve

4 - 0.8 t = 0 : t = 5

The solutions to the quadratic equation are:

t = 0, t = 5

ln (5) - ln (4)

n^{2} - 1

\frac{2 x}{3} + \frac{1}{4} = \frac{5}{6}

∣ 5 x - 7 ∣ = - 9

\frac{3}{3 2}

What are the solutions to the equation t(4-0.8t)=0 ?
The solutions to the equation t(4-0.8t)=0 are t=0,t=5
Find the zeros of t(4-0.8t)=0
The zeros of t(4-0.8t)=0 are t=0,t=5