What is factor 27x^4+54x^3-64x-128 ?

The solution to factor 27x^4+54x^3-64x-128 is (x+2)(3x-4)(9x^2+12x+16)

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factor 27x^4+54x^3-64x-128

factor

27 x^{4} + 54 x^{3} - 64 x - 128

(x + 2) (3 x - 4) (9 x^{2} + 12 x + 16)

Solution steps

27 x^{4} + 54 x^{3} - 64 x - 128

= (27 x^{4} + 54 x^{3}) + (- 64 x - 128)

Factor out

27 x^{3}

from

27 x^{4} + 54 x^{3} : 27 x^{3} (x + 2)

Factor out

- 64

from

- 64 x - 128 : - 64 (x + 2)

= 27 x^{3} (x + 2) - 64 (x + 2)

Factor out common term

x + 2

= (x + 2) (27 x^{3} - 64)

Factor

27 x^{3} - 64 : (3 x - 4) (3^{2} x^{2} + 4 \cdot 3 x + 4^{2})

= (x + 2) (3 x - 4) (3^{2} x^{2} + 4 \cdot 3 x + 4^{2})

Simplify

(x + 2) (3 x - 4) (3^{2} x^{2} + 4 \cdot 3 x + 4^{2}) : (x + 2) (3 x - 4) (9 x^{2} + 12 x + 16)

= (x + 2) (3 x - 4) (9 x^{2} + 12 x + 16)

\frac{( r + 4 )}{( - 8 )} = 16

(a^{m})^{n}

- x^{3} - 6 x^{2} - 12 x - 8

x^{3} y^{3} - 8 z^{3}

4 ∣ x - 12 ∣ + 1 = - 7 ∣ x - 12 ∣ + 1

What is factor 27x^4+54x^3-64x-128 ?
The solution to factor 27x^4+54x^3-64x-128 is (x+2)(3x-4)(9x^2+12x+16)