What is factor n^2+3n-4 ?

The solution to factor n^2+3n-4 is (n-1)(n+4)

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factor n^2+3n-4

factor

n^{2} + 3 n - 4

(n - 1) (n + 4)

Solution steps

n^{2} + 3 n - 4

Break the expression into groups

= (n^{2} - n) + (4 n - 4)

Factor out

n

from

n^{2} - n : n (n - 1)

Factor out

4

from

4 n - 4 : 4 (n - 1)

= n (n - 1) + 4 (n - 1)

Factor out common term

n - 1

= (n - 1) (n + 4)

x^{3} - 3 x^{2} + 2 x + 6

∣ - 3 + 3 i ∣

w^{4} - 8 w^{2} - 9

343 x^{3} - 64 y^{3}

\frac{27 x ^{7} y ^{8}}{27 x y ^{5}}