What are the solutions to the equation -2x^2+2x+5=0 ?

The solutions to the equation -2x^2+2x+5=0 are x=-(-1+sqrt(11))/2 ,x=(1+sqrt(11))/2

Find the zeros of -2x^2+2x+5=0

The zeros of -2x^2+2x+5=0 are x=-(-1+sqrt(11))/2 ,x=(1+sqrt(11))/2

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- 2 x^{2} + 2 x + 5 = 0

x = - \frac{- 1 + 11}{2}, x = \frac{1 + 11}{2}

Decimal Notation

x = - 1.15831 \dots, x = 2.15831 \dots

Solution steps

- 2 x^{2} + 2 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 2 ) \cdot 5}{2 ( - 2 )}

2^{2} - 4 (- 2) \cdot 5 = 211

x_{1, 2} = \frac{- 2 \pm 2 11}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 2 + 2 11}{2 ( - 2 )}, x_{2} = \frac{- 2 - 2 11}{2 ( - 2 )}

x = \frac{- 2 + 2 11}{2 ( - 2 )} : - \frac{- 1 + 11}{2}

x = \frac{- 2 - 2 11}{2 ( - 2 )} : \frac{1 + 11}{2}

The solutions to the quadratic equation are:

x = - \frac{- 1 + 11}{2}, x = \frac{1 + 11}{2}

999

\frac{1}{3} x^{2} + \frac{1}{21} x - 1 = 0

\frac{1}{6} - \frac{5}{7}

380

18 x^{2} - 24 x + 8

What are the solutions to the equation -2x^2+2x+5=0 ?
The solutions to the equation -2x^2+2x+5=0 are x=-(-1+sqrt(11))/2 ,x=(1+sqrt(11))/2
Find the zeros of -2x^2+2x+5=0
The zeros of -2x^2+2x+5=0 are x=-(-1+sqrt(11))/2 ,x=(1+sqrt(11))/2