What are the solutions to the equation 2(x-1)^2-1=0 ?

The solutions to the equation 2(x-1)^2-1=0 are x=sqrt(1/2)+1,x=-sqrt(1/2)+1

Find the zeros of 2(x-1)^2-1=0

The zeros of 2(x-1)^2-1=0 are x=sqrt(1/2)+1,x=-sqrt(1/2)+1

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2 (x - 1)^{2} - 1 = 0

x = \frac{1}{2} + 1, x = - \frac{1}{2} + 1

Decimal Notation

x = 1.70710 \dots, x = 0.29289 \dots

Solution steps

2 (x - 1)^{2} - 1 = 0

Move

1

to the right side

2 (x - 1)^{2} = 1

Divide both sides by

2

(x - 1)^{2} = \frac{1}{2}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = \frac{1}{2} : x = \frac{1}{2} + 1

Solve

x - 1 = - \frac{1}{2} : x = - \frac{1}{2} + 1

The solutions to the quadratic equation are:

x = \frac{1}{2} + 1, x = - \frac{1}{2} + 1

x^{2} - 16 \geq 1

- 70 \leq 5 k

\frac{125 x ^{2} y ^{6}}{25 x ^{5} y ^{6}}

7 q^{2} + 7 q - 14 = 0

699

What are the solutions to the equation 2(x-1)^2-1=0 ?
The solutions to the equation 2(x-1)^2-1=0 are x=sqrt(1/2)+1,x=-sqrt(1/2)+1
Find the zeros of 2(x-1)^2-1=0
The zeros of 2(x-1)^2-1=0 are x=sqrt(1/2)+1,x=-sqrt(1/2)+1