What are the solutions to the equation -x^2+x+6=0 ?

The solutions to the equation -x^2+x+6=0 are x=-2,x=3

Find the zeros of -x^2+x+6=0

The zeros of -x^2+x+6=0 are x=-2,x=3

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- x^{2} + x + 6 = 0

x = - 2, x = 3

Solution steps

- x^{2} + x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 1 ) \cdot 6}{2 ( - 1 )}

1^{2} - 4 (- 1) \cdot 6 = 5

x_{1, 2} = \frac{- 1 \pm 5}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 1 + 5}{2 ( - 1 )}, x_{2} = \frac{- 1 - 5}{2 ( - 1 )}

x = \frac{- 1 + 5}{2 ( - 1 )} : - 2

x = \frac{- 1 - 5}{2 ( - 1 )} : 3

The solutions to the quadratic equation are:

x = - 2, x = 3

5 i^{2}

\frac{5 x - 9}{4} - \frac{3 x + 5}{4} = \frac{2}{3}

\frac{8}{18}

∣ x - 2 ∣ + ∣ x - 9 ∣ + ∣ 8 - x ∣ > 13

64 v^{2} - 25 w^{2}

What are the solutions to the equation -x^2+x+6=0 ?
The solutions to the equation -x^2+x+6=0 are x=-2,x=3
Find the zeros of -x^2+x+6=0
The zeros of -x^2+x+6=0 are x=-2,x=3