What are the solutions to the equation 2x^2+6x-2=5x+1 ?

The solutions to the equation 2x^2+6x-2=5x+1 are x=1,x=-3/2

Find the zeros of 2x^2+6x-2=5x+1

The zeros of 2x^2+6x-2=5x+1 are x=1,x=-3/2

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2 x^{2} + 6 x - 2 = 5 x + 1

x = 1, x = - \frac{3}{2}

Decimal Notation

x = 1, x = - 1.5

Solution steps

2 x^{2} + 6 x - 2 = 5 x + 1

Move

1

to the left side

2 x^{2} + 6 x - 3 = 5 x

Move

5 x

to the left side

2 x^{2} + x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

1^{2} - 4 \cdot 2 (- 3) = 5

x_{1, 2} = \frac{- 1 \pm 5}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 1 + 5}{2 \cdot 2}, x_{2} = \frac{- 1 - 5}{2 \cdot 2}

x = \frac{- 1 + 5}{2 \cdot 2} : 1

x = \frac{- 1 - 5}{2 \cdot 2} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = 1, x = - \frac{3}{2}

lo g_{16} (8) = x

x^{2} + 9 < x^{2} - 8

10 x - 50

2 x^{3} - x^{2} - 8 x + 4

4 x^{3} \frac{y ^{2}}{( - 2 x ^{3} y )} + 3 x \frac{y}{( 3 y )}

What are the solutions to the equation 2x^2+6x-2=5x+1 ?
The solutions to the equation 2x^2+6x-2=5x+1 are x=1,x=-3/2
Find the zeros of 2x^2+6x-2=5x+1
The zeros of 2x^2+6x-2=5x+1 are x=1,x=-3/2