What are the solutions to the equation 0(x)=5x^2-3x+7 ?

The solutions to the equation 0(x)=5x^2-3x+7 are x= 3/10+i(sqrt(131))/(10),x= 3/10-i(sqrt(131))/(10)

Find the zeros of 0(x)=5x^2-3x+7

The zeros of 0(x)=5x^2-3x+7 are x= 3/10+i(sqrt(131))/(10),x= 3/10-i(sqrt(131))/(10)

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0 (x) = 5 x^{2} - 3 x + 7

x = \frac{3}{10} + i \frac{131}{10}, x = \frac{3}{10} - i \frac{131}{10}

Solution steps

0 \cdot (x) = 5 x^{2} - 3 x + 7

Refine

0 = 5 x^{2} - 3 x + 7

Switch sides

5 x^{2} - 3 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 5 \cdot 7}{2 \cdot 5}

Simplify

(- 3)^{2} - 4 \cdot 5 \cdot 7 : 131 i

x_{1, 2} = \frac{- ( - 3 ) \pm 131 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 131 i}{2 \cdot 5}, x_{2} = \frac{- ( - 3 ) - 131 i}{2 \cdot 5}

x = \frac{- ( - 3 ) + 131 i}{2 \cdot 5} : \frac{3}{10} + i \frac{131}{10}

x = \frac{- ( - 3 ) - 131 i}{2 \cdot 5} : \frac{3}{10} - i \frac{131}{10}

The solutions to the quadratic equation are:

x = \frac{3}{10} + i \frac{131}{10}, x = \frac{3}{10} - i \frac{131}{10}

4 x^{2} = 9 x - 3

∣ n ∣ + 2 \geq 5

- \frac{1}{3} (4 + z) z = - \frac{5}{6}

(6 - 5 i) (4 - 3 i)

\frac{16}{3} - 5

What are the solutions to the equation 0(x)=5x^2-3x+7 ?
The solutions to the equation 0(x)=5x^2-3x+7 are x= 3/10+i(sqrt(131))/(10),x= 3/10-i(sqrt(131))/(10)
Find the zeros of 0(x)=5x^2-3x+7
The zeros of 0(x)=5x^2-3x+7 are x= 3/10+i(sqrt(131))/(10),x= 3/10-i(sqrt(131))/(10)