What are the solutions to the equation 16r^2+10=0 ?

The solutions to the equation 16r^2+10=0 are r=(sqrt(5))/(2sqrt(2))i,r=-(sqrt(5))/(2sqrt(2))i

Find the zeros of 16r^2+10=0

The zeros of 16r^2+10=0 are r=(sqrt(5))/(2sqrt(2))i,r=-(sqrt(5))/(2sqrt(2))i

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16 r^{2} + 10 = 0

r = \frac{5}{2 2} i, r = - \frac{5}{2 2} i

Solution steps

16 r^{2} + 10 = 0

Move

10

to the right side

16 r^{2} = - 10

Divide both sides by

16

r^{2} = - \frac{5}{8}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = - \frac{5}{8}, r = - - \frac{5}{8}

- \frac{5}{8} = \frac{5}{2 2} i

- - \frac{5}{8} = - \frac{5}{2 2} i

r = \frac{5}{2 2} i, r = - \frac{5}{2 2} i

lo g_{5} (\frac{1}{3125})

c = 180 (4) + 250

49 a^{2} - 169

48 a^{2} - 27 b^{2}

∣ 3 x - 12 ∣ = 0

What are the solutions to the equation 16r^2+10=0 ?
The solutions to the equation 16r^2+10=0 are r=(sqrt(5))/(2sqrt(2))i,r=-(sqrt(5))/(2sqrt(2))i
Find the zeros of 16r^2+10=0
The zeros of 16r^2+10=0 are r=(sqrt(5))/(2sqrt(2))i,r=-(sqrt(5))/(2sqrt(2))i