What is expand (x-3)(x^2-3x+9) ?

The solution to expand (x-3)(x^2-3x+9) is x^3-6x^2+18x-27

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expand (x-3)(x^2-3x+9)

expand

(x - 3) (x^{2} - 3 x + 9)

x^{3} - 6 x^{2} + 18 x - 27

Solution steps

(x - 3) (x^{2} - 3 x + 9)

Distribute parentheses

= x x^{2} + x (- 3 x) + x \cdot 9 - 3 x^{2} - 3 (- 3 x) - 3 \cdot 9

Simplify

x x^{2} + x (- 3 x) + x \cdot 9 - 3 x^{2} - 3 (- 3 x) - 3 \cdot 9 : x^{3} - 6 x^{2} + 18 x - 27

= x^{3} - 6 x^{2} + 18 x - 27

1 - 8 x^{2} - 9 x^{4}

x - 3 (x^{2} - x) + 5 x + x^{2}

9 \frac{1}{4} - 4 \frac{3}{4}

16 \cdot (- 7)

\frac{2 5}{6}

What is expand (x-3)(x^2-3x+9) ?
The solution to expand (x-3)(x^2-3x+9) is x^3-6x^2+18x-27