What are the solutions to the equation 9-x^2=-8x ?

The solutions to the equation 9-x^2=-8x are x=-1,x=9

Find the zeros of 9-x^2=-8x

The zeros of 9-x^2=-8x are x=-1,x=9

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9 - x^{2} = - 8 x

x = - 1, x = 9

Solution steps

9 - x^{2} = - 8 x

Move

8 x

to the left side

9 - x^{2} + 8 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + 8 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 1 ) \cdot 9}{2 ( - 1 )}

8^{2} - 4 (- 1) \cdot 9 = 10

x_{1, 2} = \frac{- 8 \pm 10}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 8 + 10}{2 ( - 1 )}, x_{2} = \frac{- 8 - 10}{2 ( - 1 )}

x = \frac{- 8 + 10}{2 ( - 1 )} : - 1

x = \frac{- 8 - 10}{2 ( - 1 )} : 9

The solutions to the quadratic equation are:

x = - 1, x = 9

4 x + 3 \geq 2 x + 5

\frac{20 x ^{5} y ^{5}}{4 x ^{3} y ^{6}}

11 h + 9 \leq 5 h - 21

6 x^{2} - 6 > x^{2} + 13 x

16 x^{2} - 6 x^{3}

What are the solutions to the equation 9-x^2=-8x ?
The solutions to the equation 9-x^2=-8x are x=-1,x=9
Find the zeros of 9-x^2=-8x
The zeros of 9-x^2=-8x are x=-1,x=9