What is (x^2+7x+12)/(x^2-16) ?

The solution to (x^2+7x+12)/(x^2-16) is (x+3)/(x-4)

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simplify (x^2+7x+12)/(x^2-16)

simplify

\frac{x ^{2} + 7 x + 12}{x ^{2} - 16}

\frac{x + 3}{x - 4}

Solution steps

\frac{x ^{2} + 7 x + 12}{x ^{2} - 16}

Factor

x^{2} + 7 x + 12 : (x + 3) (x + 4)

= \frac{( x + 3 ) ( x + 4 )}{x ^{2} - 16}

Factor

x^{2} - 16 : (x + 4) (x - 4)

= \frac{( x + 3 ) ( x + 4 )}{( x + 4 ) ( x - 4 )}

Cancel the common factor:

x + 4

= \frac{x + 3}{x - 4}

(- x)^{2} + 2 (- x) + 3

61 \cdot 3

\frac{2 ^{4}}{( 2 ^{- 6} ) ^{- 1}}

\frac{84}{14}

\frac{4 ( 3 + c )}{4 c}

What is (x^2+7x+12)/(x^2-16) ?
The solution to (x^2+7x+12)/(x^2-16) is (x+3)/(x-4)