What is factor x^4-4x^3+7x^2-6x-18 ?

The solution to factor x^4-4x^3+7x^2-6x-18 is (x+1)(x-3)(x^2-2x+6)

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factor x^4-4x^3+7x^2-6x-18

factor

x^{4} - 4 x^{3} + 7 x^{2} - 6 x - 18

(x + 1) (x - 3) (x^{2} - 2 x + 6)

Solution steps

x^{4} - 4 x^{3} + 7 x^{2} - 6 x - 18

Use the rational root theorem

= (x + 1) \frac{x ^{4} - 4 x ^{3} + 7 x ^{2} - 6 x - 18}{x + 1}

\frac{x ^{4} - 4 x ^{3} + 7 x ^{2} - 6 x - 18}{x + 1} = x^{3} - 5 x^{2} + 12 x - 18

= (x + 1) (x^{3} - 5 x^{2} + 12 x - 18)

Factor

x^{3} - 5 x^{2} + 12 x - 18 : (x - 3) (x^{2} - 2 x + 6)

= (x + 1) (x - 3) (x^{2} - 2 x + 6)

\frac{- 8}{0}

x \cdot x + 1

lo g_{2} (16) - lo g_{2} (8)

\frac{2}{3} (3 x + 9)

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What is factor x^4-4x^3+7x^2-6x-18 ?
The solution to factor x^4-4x^3+7x^2-6x-18 is (x+1)(x-3)(x^2-2x+6)