What is the answer to 2-2m+[2m-(2-2m)]=2 ?

The answer to 2-2m+[2m-(2-2m)]=2 is m=1

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2-2m+[2m-(2-2m)]=2

2 - 2 m + [2 m - (2 - 2 m)] = 2

m = 1

Solution steps

2 - 2 m + [2 m - (2 - 2 m)] = 2

Subtract

2

from both sides

2 - 2 m + [2 m - (2 - 2 m)] - 2 = 2 - 2

Simplify

- 2 m + [2 m - (2 - 2 m)] = 0

Remove parentheses:

(a) = a

- 2 m + 2 m - (2 - 2 m) = 0

Add similar elements:

- 2 m + 2 m = 0

- (2 - 2 m) = 0

Divide both sides by

- 1

2 - 2 m = 0

Move

2

to the right side

- 2 m = - 2

Divide both sides by

- 2

m = 1

(x - 2) x - \frac{x + 2}{3} - \frac{( x - 2 ) ( x + 2 )}{2} = (x - 2)^{2} - 4

7 x + 8 - 9 (x + 1) = 3 x + 2

\frac{x ^{\frac{2}{5}} y}{x y ^{- \frac{1}{3}}}

x^{2} + \frac{8 x}{3} = - \frac{7}{9}

\frac{1}{x + 3} > (x + 1)

What is the answer to 2-2m+[2m-(2-2m)]=2 ?
The answer to 2-2m+[2m-(2-2m)]=2 is m=1
Solve for m: 2-2m+[2m-(2-2m)]=2
The solution is m=1