en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4|t+1|>= 16

Solution

4 ∣ t + 1 ∣ \geq 16

Solution

t \leq - 5 or t \geq 3

+1

Interval Notation

(- \infty, - 5] \cup [3, \infty)

Solution steps

4 ∣ t + 1 ∣ \geq 16

Divide both sides by

4

∣ t + 1 ∣ \geq 4

Apply absolute rule: If

∣ u ∣ \geq a, a > 0

then

u \leq - a

or

u \geq a

t + 1 \leq - 4 or t + 1 \geq 4

t + 1 \leq - 4 or t + 1 \geq 4

t \leq - 5 or t \geq 3

Popular Examples

simplify (sqrt(72))/(sqrt(6))simplify

\frac{72}{6}

simplify \sqrt[3]{104}simplify

\frac{x}{4} + 1 = 7

0.3 x^{2} + 1.4 x = 0

5.23x^2-4.1x+5.7=0

5.23 x^{2} - 4.1 x + 5.7 = 0

Frequently Asked Questions (FAQ)

What is 4|t+1|>= 16 ?
The solution to 4|t+1|>= 16 is t<=-5\lor t>= 3