What are the solutions to the equation h(9h+5)=0 ?

The solutions to the equation h(9h+5)=0 are h=0,h=-5/9

Find the zeros of h(9h+5)=0

The zeros of h(9h+5)=0 are h=0,h=-5/9

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h (9 h + 5) = 0

h = 0, h = - \frac{5}{9}

Decimal Notation

h = 0, h = - 0.55555 \dots

Solution steps

h (9 h + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

h = 0 or 9 h + 5 = 0

Solve

9 h + 5 = 0 : h = - \frac{5}{9}

The solutions to the quadratic equation are:

h = 0, h = - \frac{5}{9}

5 x - 4 = 6

12 a^{3} + 4 a^{2} + 3 ab + b

∣ x + 5 ∣ \geq 4

x^{2} + 7 x + 5 = 0

- 3 k^{4} + 18 k^{3} - 24 k^{2}

What are the solutions to the equation h(9h+5)=0 ?
The solutions to the equation h(9h+5)=0 are h=0,h=-5/9
Find the zeros of h(9h+5)=0
The zeros of h(9h+5)=0 are h=0,h=-5/9