What are the solutions to the equation w^2-5w=14 ?

The solutions to the equation w^2-5w=14 are w=7,w=-2

Find the zeros of w^2-5w=14

The zeros of w^2-5w=14 are w=7,w=-2

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w^{2} - 5 w = 14

w = 7, w = - 2

Solution steps

w^{2} - 5 w = 14

Move

14

to the left side

w^{2} - 5 w - 14 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 14) = 9

w_{1, 2} = \frac{- ( - 5 ) \pm 9}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- ( - 5 ) + 9}{2 \cdot 1}, w_{2} = \frac{- ( - 5 ) - 9}{2 \cdot 1}

w = \frac{- ( - 5 ) + 9}{2 \cdot 1} : 7

w = \frac{- ( - 5 ) - 9}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

w = 7, w = - 2

90 x + 50 = 410

5 - 2 y = 7

x^{2} + 2 x - 80 = 0

\frac{- 4 p q ^{5} r ^{3}}{8 p ^{2} q ^{2} r ^{10}}

\frac{5}{8} - \frac{6}{8}

What are the solutions to the equation w^2-5w=14 ?
The solutions to the equation w^2-5w=14 are w=7,w=-2
Find the zeros of w^2-5w=14
The zeros of w^2-5w=14 are w=7,w=-2