What are the solutions to the equation y^2-6y+34=0 ?

The solutions to the equation y^2-6y+34=0 are y=3+5i,y=3-5i

Find the zeros of y^2-6y+34=0

The zeros of y^2-6y+34=0 are y=3+5i,y=3-5i

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y^{2} - 6 y + 34 = 0

y = 3 + 5 i, y = 3 - 5 i

Solution steps

y^{2} - 6 y + 34 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 34}{2 \cdot 1}

Simplify

(- 6)^{2} - 4 \cdot 1 \cdot 34 : 10 i

y_{1, 2} = \frac{- ( - 6 ) \pm 10 i}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 6 ) + 10 i}{2 \cdot 1}, y_{2} = \frac{- ( - 6 ) - 10 i}{2 \cdot 1}

y = \frac{- ( - 6 ) + 10 i}{2 \cdot 1} : 3 + 5 i

y = \frac{- ( - 6 ) - 10 i}{2 \cdot 1} : 3 - 5 i

The solutions to the quadratic equation are:

y = 3 + 5 i, y = 3 - 5 i

(x + 3)^{2} < 2

[b + 6] + 6 = - 7

\frac{1}{3 + 2 i}

\frac{2 n - 8}{n ^{2} - 16}

12 x - 5 = 9 x^{2}

What are the solutions to the equation y^2-6y+34=0 ?
The solutions to the equation y^2-6y+34=0 are y=3+5i,y=3-5i
Find the zeros of y^2-6y+34=0
The zeros of y^2-6y+34=0 are y=3+5i,y=3-5i