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What are the solutions to the equation 1x^2+4x+1=0 ?
The solutions to the equation 1x^2+4x+1=0 are x=-2+sqrt(3),x=-2-sqrt(3)Find the zeros of 1x^2+4x+1=0
The zeros of 1x^2+4x+1=0 are x=-2+sqrt(3),x=-2-sqrt(3)