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Frequently Asked Questions (FAQ)
What are the solutions to the equation 3y^2+6y-4=0 ?
- The solutions to the equation 3y^2+6y-4=0 are y=(-3+sqrt(21))/3 ,y=-(3+sqrt(21))/3
Find the zeros of 3y^2+6y-4=0
- The zeros of 3y^2+6y-4=0 are y=(-3+sqrt(21))/3 ,y=-(3+sqrt(21))/3