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Frequently Asked Questions (FAQ)
What are the solutions to the equation 3x^2+4x+7=0 ?
- The solutions to the equation 3x^2+4x+7=0 are x=-2/3+i(sqrt(17))/3 ,x=-2/3-i(sqrt(17))/3
Find the zeros of 3x^2+4x+7=0
- The zeros of 3x^2+4x+7=0 are x=-2/3+i(sqrt(17))/3 ,x=-2/3-i(sqrt(17))/3