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Frequently Asked Questions (FAQ)
What are the solutions to the equation 3x^2+17=6 ?
- The solutions to the equation 3x^2+17=6 are x=sqrt(11/3)i,x=-sqrt(11/3)i
Find the zeros of 3x^2+17=6
- The zeros of 3x^2+17=6 are x=sqrt(11/3)i,x=-sqrt(11/3)i