What are the solutions to the equation x^2+9x=-20 ?

The solutions to the equation x^2+9x=-20 are x=-4,x=-5

Find the zeros of x^2+9x=-20

The zeros of x^2+9x=-20 are x=-4,x=-5

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x^{2} + 9 x = - 20

x = - 4, x = - 5

Solution steps

x^{2} + 9 x = - 20

Move

20

to the left side

x^{2} + 9 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 20 = 1

x_{1, 2} = \frac{- 9 \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 9 + 1}{2 \cdot 1}, x_{2} = \frac{- 9 - 1}{2 \cdot 1}

x = \frac{- 9 + 1}{2 \cdot 1} : - 4

x = \frac{- 9 - 1}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = - 4, x = - 5

∣ x + 8 ∣ = - 3

- 7 x y^{3} (- 2 x^{2} y^{4})

(2)^{\frac{1}{2}}

3 x - 21 x - 108 + 18 x + 108 = 0

299 - 15 [- (65 - 48) - 3 (100 - (- 540))]

What are the solutions to the equation x^2+9x=-20 ?
The solutions to the equation x^2+9x=-20 are x=-4,x=-5
Find the zeros of x^2+9x=-20
The zeros of x^2+9x=-20 are x=-4,x=-5