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Frequently Asked Questions (FAQ)
What are the solutions to the equation 4x^2+80=0 ?
- The solutions to the equation 4x^2+80=0 are x=2sqrt(5)i,x=-2sqrt(5)i
Find the zeros of 4x^2+80=0
- The zeros of 4x^2+80=0 are x=2sqrt(5)i,x=-2sqrt(5)i