What are the solutions to the equation (x-1)^2-1=0 ?

The solutions to the equation (x-1)^2-1=0 are x=2,x=0

Find the zeros of (x-1)^2-1=0

The zeros of (x-1)^2-1=0 are x=2,x=0

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(x - 1)^{2} - 1 = 0

x = 2, x = 0

Solution steps

(x - 1)^{2} - 1 = 0

Move

1

to the right side

(x - 1)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = 1 : x = 2

Solve

x - 1 = - 1 : x = 0

The solutions to the quadratic equation are:

x = 2, x = 0

(x + 2) (x + 5) = 28

15 f^{2} + 2 f - 45

\frac{8 k + 9}{18} - \frac{2 k + 1}{18}

∣ x - 7 ∣ = 27

\frac{13}{3} = \frac{u}{11}

What are the solutions to the equation (x-1)^2-1=0 ?
The solutions to the equation (x-1)^2-1=0 are x=2,x=0
Find the zeros of (x-1)^2-1=0
The zeros of (x-1)^2-1=0 are x=2,x=0