What are the solutions to the equation 5x^2+14x+8=0 ?

The solutions to the equation 5x^2+14x+8=0 are x=-4/5 ,x=-2

Find the zeros of 5x^2+14x+8=0

The zeros of 5x^2+14x+8=0 are x=-4/5 ,x=-2

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5 x^{2} + 14 x + 8 = 0

x = - \frac{4}{5}, x = - 2

Decimal Notation

x = - 0.8, x = - 2

Solution steps

5 x^{2} + 14 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 5 \cdot 8}{2 \cdot 5}

1 4^{2} - 4 \cdot 5 \cdot 8 = 6

x_{1, 2} = \frac{- 14 \pm 6}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 14 + 6}{2 \cdot 5}, x_{2} = \frac{- 14 - 6}{2 \cdot 5}

x = \frac{- 14 + 6}{2 \cdot 5} : - \frac{4}{5}

x = \frac{- 14 - 6}{2 \cdot 5} : - 2

The solutions to the quadratic equation are:

x = - \frac{4}{5}, x = - 2

- 4 x^{3} (y - 2) - 32 (2 - y)

4 x^{2} - 32 x + 64

(2 + i)^{2}

\frac{x ^{2} + 5 x y + 6 y ^{2}}{x + 2 y}

2 x + 3 \geq 3 x + 1 > x + 4

What are the solutions to the equation 5x^2+14x+8=0 ?
The solutions to the equation 5x^2+14x+8=0 are x=-4/5 ,x=-2
Find the zeros of 5x^2+14x+8=0
The zeros of 5x^2+14x+8=0 are x=-4/5 ,x=-2